2x^2-51x+72=0

Solution for 2x^2-51x+72=0 equation:

2x^2-51x+72=0

a = 2; b = -51; c = +72;
Δ = b2-4ac
Δ = -512-4·2·72
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-45}{2*2}=\frac{6}{4}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+45}{2*2}=\frac{96}{4}
=24
$